TCS Coding Question - Valid Keyword - One programming language has the following keywords that cannot be used as identifiers

 Problem Statement 
Valid Keyword
One programming language has the following keywords that cannot be used as identifiers:

break, case, continue, default, defer, else, for, func, goto, if, map, range, return, struct, type, var

Write a program to find if the given word is a keyword or not.

Test Case: 

Case 1

Input – defer

Expected Output – defer is a keyword

Case 2

Input – while

Expected Output – while is not a keyword

Programming Language - C

#include <stdio.h>
#include <string.h>
int main() {

   char keywords[16][10]={"break", "case", "continue", "default", "defer", "else","for", 
		"func", "goto", "if", "map", "range", "return", "struct", "type", "var"} ;
	
   char input[]="";
   scanf("%s",input);
   
   int flag=0,i;
   
   for(i = 0; i < 32; i++) {
      if(strcmp(str,keywords[i])==0) {
         flag=1;
      }
   }
   if(flag==1)
      printf("%s is a keyword",str);
   else
      printf("%s is not a keyword",str);
}

Programming Language - Java

package codingExample;

import java.util.Scanner;

public class IsKeyword {

	public static void main(String[] args) {

		String str[] = { "break", "case", "continue", "default", "defer", "else",
				"for", "func", "goto", "if", "map",	"range", "return", "struct", "type", "var" };

		boolean isKeyword = false;
		Scanner sc = new Scanner(System.in);
		String input = sc.nextLine();

		for (int i = 0; i < 16; i++) {

			if (str[i].equals(input)) {
				isKeyword = true;
				break;
			}
		}
		if (isKeyword) {
			System.out.println(input + " is a keyword");
		} else {
			System.out.println(input + " is not a keyword");
		}
	}
}

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